I need to write an equation for when the slope is 5/3 and the y-intercept is (0,-3)
I got Y = 5/3x +o
Cn someone verify for me please also i don't know how to find the slope of x=1
y = m x + b
m = slope
b = y-intercept
In this case :
slope m = 5 / 3
y-intercept = - 3
y = ( 5 / 3 ) x + ( - 3 )
y = ( 5 / 3 ) x - 3
Line x = 1
are parallel with y-axis and passing through point x = 1
The angle theta a line makes with the positive x axis is closely related to the slope m via the tangent function:
m = tan ( theta )
In this case theta = 90 °
tan 90 ° = infinity
Slope of line x = 1
m = infinity
Thank youuu
To write the equation of a line when you have the slope and y-intercept, you can use the slope-intercept form: y = mx + b.
Given that the slope is 5/3 and the y-intercept is (0, -3), you can substitute these values into the equation.
So the equation would be:
y = (5/3)x - 3
Regarding your question about finding the slope of x = 1, it seems that you have an equation in the form of x = a constant value. When working with vertical lines like this, the slope is undefined because these lines are parallel to the y-axis and do not have a change in y for any change in x.