FIND THE SLOP of line containing points(-2,8) and (3,5)
-3/5
Two point form of linear equation :
y - y 1 = ( y 2 - y 1 ) * ( x - x 1 ) / ( x 2 - x 1 )
Te slope is explicitly given as
m = ( y 2 - y 1) / ( x 2 - x 1 )
In this case :
x 1 = - 2
x 2 = 3
y 1 = 8
y 2 = 5
m = ( y 2 - y 1 ) / ( x 2 - x 1 )
m = ( 5 - 8 ) / [ 3 - ( - 2 ) ]
m = - 3 / ( 3 + 2 )
m = - 3 / 5 = - 0.6
To find the slope of a line passing through two points, you can use the formula:
slope = (y2 - y1) / (x2 - x1)
In this case, the given points are (-2, 8) and (3, 5). Let's label them as (x1, y1) and (x2, y2) respectively:
x1 = -2, y1 = 8
x2 = 3, y2 = 5
Next, substitute the values into the slope formula:
slope = (5 - 8) / (3 - (-2))
= (-3) / (3 + 2)
= -3 / 5
Therefore, the slope of the line passing through the points (-2, 8) and (3, 5) is -3/5.