A cell phone, when weighed in air has a weight of 5.5 newton. When completely immersed in water, however, it has a weight of 3.3 newton. Find the volume of the cell phone.

Let P = 5.5 N, G= 3.3 N

Buoyancy force F= P - G or according to the definition
F= Mg= D•V•g.
where D is the density of water.
P - G = D•V•g,
V = (P – G)/D•g =(5.5-3.3)/1000•9.8 =2.24•10^-4 m^3

To find the volume of the cell phone, we can make use of Archimedes' Principle. Archimedes' Principle states that the buoyant force exerted on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

1. Start by calculating the weight of the water displaced by the cell phone.
Weight of the water displaced = Weight in air - Weight in water
Weight of the water displaced = 5.5 N - 3.3 N
Weight of the water displaced = 2.2 N

2. Since the weight of the water displaced is equal to the buoyant force, it is also equal to the weight of the cell phone when submerged.

3. Now, we need to convert the weight of the water displaced into mass using the formula:
Weight = mass x acceleration due to gravity (W = mg)

Rearranging the formula to solve for mass:
mass = Weight / acceleration due to gravity

Let's assume the acceleration due to gravity is approximately 9.8 m/s^2 (standard value).

mass = 2.2 N / 9.8 m/s^2
mass ≈ 0.224 kg

4. Finally, we can calculate the volume of the cell phone using the formula:
Volume = mass / density

However, we need the density of water to proceed. The density of water is approximately 1000 kg/m^3 (standard value).

Volume = 0.224 kg / 1000 kg/m^3
Volume ≈ 0.000224 m^3

So, the volume of the cell phone is approximately 0.000224 cubic meters.