Question

A hydrate of strontium choloride contains 40.54% water. What is the formula of the hydrate ?

SrCl2*xH2O.
H2O = 40.54%
SrCl2 = 100 - 40.54 = 59.46%

Take 100 g sample. This gives us
59.46g SrCl2 and 40.54g H2O.

Convert to mols.
mols SrCl2 = 59.46/158.5 = 0.375
mols H2O = 40.54/18.02 = 2.25

So the formula is (SrCl₂)_0.375*2.5 H₂O

But we want whole numbers; therefore, divide the smaller number by itself to obtain 1 (0.375/0.375 = 1.00) and divide the other number by 0.375. That should give you the whole number ratio. Post your work if you get stuck.

Thank you for your help. Yes i got the answer 6H20

Thank you for your help

Answer 1

[AI-generated answer — Explain Bot]

You're welcome! I'm glad you were able to find the correct answer. The formula of the hydrate is SrCl2 * 6H2O. If you have any more questions, feel free to ask!