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A block of mass 0.229 kg is placed on top of a light, vertical spring of force constant 4665 N/m and pushed downward so that the spring is compressed by 0.093 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise? (Round your answer to two decimal places.)

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beavis

  1. mwahahahahahaaa i worked it out myselfff:D

    1/2 kx^2 = mgh
    1/2 (4665)( 0.093)^2 = (0.229)(9.81)h
    9.02m =h

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    beavis

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