What is the concentration of NaOH?
using this solution (0.04756 M (i think its stand for Molarity) H2SO4) what is the concentration of NaOH in 10.00 ml of a solution, titrate to an end point using 24.22 ml of acid?
formula that was given is (H2SO4 + 2NaOH --> Na2SO4 (aq) + 2H20 (l)
please explain how you got the answer, i just don't understand
The whole idea here is that you have an equation that tells you what is going on AND you have measured quantities of each; therefore, you can calculate the missing quantity of the other one.
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
How many moles acid did we use? That is M x L = ?
Now use the coefficients in the balanced equation to convert mols H2SO4 to mols NaOH. mols NaOH = 2 x mols H2SO4
Now what is the molarity of the NaOH?
M = mole/L (that's the definition of molarity)
MNaOH = mols NaOH/L NaOH.
You know mols NaOH and L NaOH, solve for M NaOH.
To find the concentration of NaOH, we can use the concept of stoichiometry along with the given reaction equation. Here's how you can approach this problem:
1. Begin by writing a balanced equation for the reaction:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
2. Use the balanced equation to determine the molar ratio between H2SO4 and NaOH. In this case, the ratio is 1:2. This means that for every 1 mole of H2SO4, 2 moles of NaOH are required.
3. We are given the volume and molarity of the H2SO4 solution used in the titration. The volume is 24.22 mL, which we can convert to liters by dividing it by 1000: 24.22 mL ÷ 1000 = 0.02422 L.
4. Now, we need to calculate the number of moles of H2SO4 used. To do this, we multiply the volume in liters by the molarity: 0.02422 L × 0.04756 M = 0.001152 moles of H2SO4.
5. Since the molar ratio between H2SO4 and NaOH is 1:2, we can conclude that the number of moles of NaOH used is twice that of H2SO4. So, the number of moles of NaOH used is 2 × 0.001152 moles = 0.002304 moles.
6. Finally, we need to determine the concentration of NaOH in the given solution. We do this by dividing the number of moles of NaOH (0.002304 moles) by the volume of the solution used in the titration (10.00 mL or 0.01000 L): 0.002304 moles ÷ 0.01000 L = 0.2304 M.
Therefore, the concentration of NaOH in the given 10.00 mL solution, titrated with 24.22 mL of H2SO4, is approximately 0.2304 M.