35.00mL of 0.250M KOH solution is required to completely neutralize 10.50mL of H2SO4 solution. what is the molarity of the sulfuric acid solution
KOH(aq)+ H2SO4 -------> K2SO4(aq) +H2O(l
2KOH(aq)+ H2SO4 -------> K2SO4(aq) +H2O(l)
Note that I have balanced the equation.
mols KOH = M x L = ?
moles H2SO4 = mols KOH x 1/2
M H2SO4 = mols H2SO4/L H2SO4posted by DrBob222