What is the electron configuration for the transition metal ion(s) in each of the following compounds?
Na2[TaF7]
Cant seem to figure this one out...
To determine the electron configuration for the transition metal ion(s) in Na2[TaF7], we need to know the atomic number of the transition metal element involved, which is tantalum (Ta) with an atomic number of 73.
First, let's determine the electron configuration of a neutral tantalum atom:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d³
Next, we need to consider the number of electrons it loses or gains to become an ion.
In this case, Na2[TaF7] indicates the presence of two sodium (Na) atoms and seven fluoride (F) atoms. Sodium loses one electron to achieve a stable electron configuration, while fluorine gains one electron to achieve a stable electron configuration.
Since we have two sodium atoms, we will multiply the number of electrons lost by sodium by two. The total electrons lost by sodium is 2 × 1 = 2 electrons.
Since we have seven fluoride atoms, we will multiply the number of electrons gained by fluorine by seven. The total electrons gained by fluorine is 7 × 1 = 7 electrons.
Based on the number of electrons lost and gained, we can determine the electron configuration of the transition metal ion in Na2[TaF7].
The electron configuration of [Ta] will be the neutral electron configuration minus the total electrons lost and plus the total electrons gained:
Neutral electron configuration for Ta: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d³
Total electrons lost: 2 electrons
Total electrons gained: 7 electrons
Calculating the electron configuration:
[Ta] = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d³ - 2e⁻ + 7e⁻
Simplifying the electron configuration:
[Ta] = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁵
Therefore, the electron configuration for the transition metal ion in Na2[TaF7] is [Ta] = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁵.