Ccalculate the molarity of the resulting solution when 125.0 ml of water is added to 350.0 ml of a 3.75 M solution of HCl
3.75 M is diluted from 350.0 to (350.0 + 125.0) so
3.75 M x 350.0/475.0 = ??M.
There is another way to do this; i.e., to rely on the definition, always a sure thing. The definition of molarity is molarity = # mols/L.
How many mols in 350.0 mL of 3.75 M HCl? That will be 0.350 x 3.75 = 1.3125 mols. Then what is the molarity when the volume is increased to 350.0 + 125.0 = 475.0 mL = 0.4750 L. That will be 1.3125 mols/0.475 L = 2.7632 which rounds to 2.76 to 3 significant figures. Just as a check, make sure this number agrees with the answer above.
To calculate the molarity of the resulting solution, you need to consider the dilution of the original solution.
The formula for dilution is:
M1V1 = M2V2
Where:
M1 = initial molarity of the solution
V1 = initial volume of the solution
M2 = final molarity of the solution
V2 = final volume of the solution
In this case, the initial molarity (M1) is 3.75 M and the initial volume (V1) is 350.0 ml. The final volume (V2) is the sum of the initial volume and the volume of water added, which is 350.0 ml + 125.0 ml = 475.0 ml.
Now, let's plug the values into the formula:
(3.75 M) * (350.0 ml) = (M2) * (475.0 ml)
M2 = (3.75 M * 350.0 ml) / 475.0 ml
M2 = 2.77 M
Therefore, the molarity of the resulting solution after adding 125.0 ml of water to 350.0 ml of a 3.75 M solution of HCl is approximately 2.77 M.
To calculate the molarity of the resulting solution, you need to consider the moles of solute (HCl) and the total volume of the resulting solution.
First, calculate the moles of HCl in the original 350.0 ml 3.75 M solution. Molarity (M) is defined as the number of moles of solute per liter of solution.
Moles of HCl = Molarity (M) x Volume (L)
= 3.75 moles/L x (350.0 ml / 1000 ml/L)
= 3.75 x 0.3500
= 1.3125 moles
Next, calculate the total volume of the resulting solution. This would be the sum of the volume of the original HCl solution and the volume of water added.
Total volume = 350.0 ml + 125.0 ml
= 475.0 ml
Finally, calculate the molarity of the resulting solution using the moles of HCl and the total volume.
Molarity (M) = Moles of solute / Volume of solution (L)
= 1.3125 moles / (475.0 ml / 1000 ml/L)
= 1.3125 / 0.4750
= 2.76 M
Therefore, the molarity of the resulting solution when 125.0 ml of water is added to 350.0 ml of a 3.75 M solution of HCl is 2.76 M.