a saturated solution of a salt X contains 0.28g of the salt in 100cm3 of solution at 25degree centigrate, what is the solubility of the salt X at this temperature (R.m.m of X=56)
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I think i answered this earlier.(above.)
To find the solubility of the salt X at 25 degrees Celsius, we need to calculate the amount of salt that can dissolve in 100 cm^3 of solution at this temperature.
The given information is:
Mass of salt X = 0.28g
Volume of solution = 100 cm^3
R.m.m of salt X = 56 (Relative Molecular Mass)
The solubility can be calculated using the following formula:
Solubility = Mass of solute / Volume of solvent
Since the mass of the solute is given and the volume of solvent is 100 cm^3, we can plug in the values into the formula:
Solubility = 0.28g / 100 cm^3 = 0.0028 g/cm^3
Therefore, the solubility of salt X at 25 degrees Celsius is 0.0028 g/cm^3.
To find the solubility of the salt X at this temperature, we need to determine the amount of salt that can dissolve in 100 cm3 of solution.
The given information tells us that 0.28 g of the salt X is dissolved in 100 cm3 of solution.
To convert this information into solubility, we divide the mass of the dissolved salt (0.28 g) by the volume of the solution (100 cm3) and multiply by 100 to express the solubility as a percentage.
Solubility (in g/100 cm3) = (mass of salt X / volume of solution) * 100
Solubility = (0.28 g / 100 cm3) * 100
Solubility = 0.28 g
Therefore, the solubility of the salt X at this temperature is 0.28 g/100 cm3 or 0.28%.