what is the lateral area of a regular pyramid with a base 6 and slant height 8?????????????
find the area of each of the triangles
area = (1/2)base x height
= (1/2)(6)(8) = 24
So you have 4 of these plus the base.
see
http://math.about.com/od/formulas/ss/surfaceareavol_5.htm
I am assuming that by "slant height" you mean the height of the triangle and not the distance along the edge of the pyramid.
To find the lateral area of a regular pyramid, you need to know the base perimeter and the slant height.
Step 1: Find the base perimeter.
Since the base of the pyramid is a regular polygon, we can find the perimeter by multiplying the length of one side by the number of sides. In this case, the base has 6 sides with a length of 6, so the base perimeter is 6 * 6 = 36.
Step 2: Calculate the lateral area.
The lateral area of a regular pyramid is equal to half the product of the base perimeter and the slant height. In this case, the slant height is given as 8.
So, the lateral area = 1/2 * base perimeter * slant height = 1/2 * 36 * 8 = 18 * 8 = 144.
Therefore, the lateral area of the regular pyramid with a base length of 6 and slant height of 8 is 144 square units.