if the mean radius of the moon is 1.73x10^6m and its mass is 7.35x10^22kg.determin the average speed?
which speed? rotation speed, orbital speed, speed of a falling body?
Sorry Orbital speed
To determine the average speed of the moon, you need to first calculate the moon's orbital velocity. The orbital velocity can be calculated using the formula:
v = √(GM/r)
Where:
v = orbital velocity
G = gravitational constant (6.67430 × 10^-11 m^3 kg^-1 s^-2)
M = mass of the moon (7.35 × 10^22 kg)
r = radius of the moon (1.73 × 10^6 m)
Plugging in the values:
v = √((6.67430 × 10^-11 m^3 kg^-1 s^-2) * (7.35 × 10^22 kg) / (1.73 × 10^6 m))
Calculating this expression will give you the orbital velocity of the moon. To convert the orbital velocity to average speed, you need to divide it by the square root of 2:
Average Speed = v / √2
Performing the calculation will give you the average speed of the moon.
To determine the average speed of the moon, we need to use the equation that relates the speed of an object to its radius and mass.
The formula is:
Average speed = sqrt(2 * gravitational constant * mass / radius)
In this case, the mean radius of the moon is given as 1.73x10^6m, and its mass is given as 7.35x10^22kg. We can assume that the gravitational constant is 6.67430x10^-11 m^3 kg^-1 s^-2.
Plugging in the values into the formula, we have:
Average speed = sqrt(2 * 6.67430x10^-11 m^3 kg^-1 s^-2 * 7.35x10^22kg / 1.73x10^6m)
Simplifying the equation:
Average speed = sqrt(9.73324705x10^12 m^3s^-2)
Calculating the square root:
Average speed = 3.12x10^6 m/s
Therefore, the average speed of the moon is approximately 3.12x10^6 m/s.