what are the solute particles present in boric acid (H3BO3)?
I assume you mean in a water solution.
I will write it as B(OH)3.
B(OH)3 + HOH ==> H^+ + B(OH)4^-
H3BO3 is not a Bronsted-Lowry acid but it acts as a Lewis acid.
the question was to check all that apply:
BO33-
H+
H3BO22+
O2-
H3BO3
OH -
It doesn't make sense to me to talk about solute particles when there is no solvent. In water solution the particles would be H^+, H3BO3, and B(OH)4^- but that last one is not listed.
To determine the solute particles present in boric acid (H3BO3), we need to understand its chemical formula.
The formula H3BO3 indicates that boric acid consists of three hydrogen atoms (H), one boron atom (B), and three oxygen atoms (O).
To classify the solute particles, we need to consider how the compound dissociates or breaks apart when dissolved in water. In the case of boric acid, it doesn't completely dissociate into ions like some other acids. Instead, it partially dissociates into ions or forms weak bonds with water molecules.
When boric acid dissolves in water, it forms ions by accepting a proton (H+) from a water molecule. This results in the formation of a complex ion called the borate ion (B(OH)4-).
Therefore, in an aqueous solution of boric acid, the solute particles present are the undissociated boric acid molecules (H3BO3) and the borate ions (B(OH)4-).
In summary, the solute particles present in boric acid (H3BO3) are undissociated boric acid molecules (H3BO3) and borate ions (B(OH)4-).