In a pet store the number of dogs is 11 more than 3 times the number of cats. If the pet store has 21 dogs. How many cars does it have?
Question 2.
In the pet store the number of birds is 10 less than twice the number of rabbits. If the pet store. Had 56. Birds. How many rabbits does it have?
It would help if you proofread your questions before you posted them.
1. 21 = 3x + 11
2. 56 = 2x - 10
Solve for x.
12 because i just know
To solve these types of problems, we need to establish equations based on the given information and use basic algebra to find the answers.
For Question 1:
Let's assume the number of cats is represented by the variable 'c'. According to the problem, the number of dogs is 11 more than 3 times the number of cats, which translates to 3c + 11.
Given that there are 21 dogs, we set up the equation 3c + 11 = 21 and solve it for 'c':
3c + 11 = 21
Subtract 11 from both sides:
3c = 10
Divide by 3:
c = 10/3
Since we can't have a fraction of a cat, we can conclude that there are 10/3 cats in the pet store. However, the question likely expects a whole number answer. If we assume that the pet store only deals with whole numbers, we can assume that there are either 3 cats or 4 cats in the store.
For Question 2:
Similarly, let's assume the number of rabbits is represented by the variable 'r'. According to the problem, the number of birds is 10 less than twice the number of rabbits, which translates to 2r - 10.
Given that there are 56 birds, we set up the equation 2r - 10 = 56 and solve it for 'r':
2r - 10 = 56
Add 10 to both sides:
2r = 66
Divide by 2:
r = 66/2
r = 33
Therefore, the pet store has 33 rabbits.