A cylindrical oil storage tank 12 feet in diameter and 17feet long is lying on its side. Suppose the tank is half full of oil weighing 85 lb per cubic foot. What's the total force on one endof the tank?

To find the total force on one end of the tank, we need to calculate the weight of the oil in the tank and determine the force it exerts on the end.

First, let's calculate the volume of the oil in the tank. The tank is half full, so the volume of the oil is half the volume of the tank.

The volume of a cylinder is given by the formula: V = πr^2h, where r is the radius of the cylinder and h is its height.

Given that the diameter of the tank is 12 feet, the radius (r) is half the diameter, which is 12/2 = 6 feet.

The length of the tank is 17 feet, so h = 17 feet.

Substituting the values into the formula, we have:

V = π(6^2)(17) = 612π cubic feet

Next, let's find the weight of the oil using the given weight per cubic foot.

The weight of the oil is given as 85 lb per cubic foot, so the total weight of the oil is:

Weight = (Volume of oil) x (Weight per cubic foot)
= (612π) x 85 lb

Now, we need to determine the force exerted by this weight on the end of the tank.

Since force (F) is equal to the weight (W) acting vertically downward, the force exerted on the end of the tank is:

Force = Weight
= (612π) x 85 lb

To find the numerical value of this force, we can plug in the value of π as approximately 3.14:

Force = (612 x 3.14) x 85 lb

Calculating this will give you the total force on one end of the tank.

Answer is B 6120