a cyclist pedals at a constant velocity of 15m.s-1 on a level road. the power delivered by the cyclist is 240W. what is the magnitude of the frictional foce acting against the motion?

P=Fv(240÷15)= 16N

To find the magnitude of the frictional force acting against the motion, we need to use the formula for power and the equation for frictional force.

First, let's recall the formula for power:

Power = Force x Velocity

Given that the power delivered by the cyclist is 240W and the velocity is 15m/s, we can rearrange the formula to solve for force:

Force = Power / Velocity

Substituting the given values:

Force = 240W / 15m/s
Force = 16 N

So, the magnitude of the frictional force acting against the motion is 16 Newtons.