The explosive residue contains carbon, hydrogen and nitrogen where the percentage of nitrogen is high, calculate it from 0.5g of residue which eliminates ammonia gas on reaction with sodium hydroxide, and absorb by 50mL of Nby10 H2SO4. Unused acid is neutralized/titrated with 14mL potassium hydroxide

i am using the formula
% of nitrogen = (1.4*Nacid*Vacid)/(weight of residue)

is the answer 14%
or 3.9%

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asked by Farah
  1. I can't tell what you've done.

    posted by DrBob222

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