# algebra

1. logx+log(x+48)=2

14.log50+log(x/2)=2

23.log72-log(2x/3)=0

Could someone please explain to me how to solve these?

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2. thanks, but how do i solve them?

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3. remember the rule of logs?

Log (ab)= loga + logb so, take 14 as an example:

log50 + log(x/2)=2
log(50x/2)=2
50x/2= antilog2
solve for x

On 23, the formula is

log(a/b)= loga - logb

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bobpursley
4. thanks!

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