what is the molarity of a HCl solution that contains 13.0 g of HCl in 125 mL of solution?
Answer in units of M
is it 3791.944 ?
No, not close.
Show your work and I'll find the error.
13(36.461)=473.993
473.993/.125=3791.944
mol = g/molar mass
You multiplied. You should divide.
13.0/36.461 = ?
Then ?/0.125 = x
2.852
Some profs would not give you credit for that answer even though it is close. The correct answer is 2.85M. Why is 2.852 wrong? Because you are allowed only three significant figures (dictated by 3 in 13.0 and 3 in 125); therefore, you may have only 3 in the answer. 2.85 satisfies that and 2.852 does not for it has 4 s.f.
To find the molarity of a solution, you need to use the formula:
Molarity (M) = moles of solute / volume of solution in liters
First, we need to convert the given mass of HCl into moles. The molar mass of HCl is 36.46 g/mol.
moles of HCl = mass of HCl / molar mass of HCl
moles of HCl = 13.0 g / 36.46 g/mol
moles of HCl = 0.356 mol
Next, we need to convert the volume of the solution from milliliters (mL) to liters (L). There are 1000 mL in 1 L.
volume of solution = 125 mL / 1000 mL/L
volume of solution = 0.125 L
Now, we can use the formula to calculate the molarity:
Molarity (M) = moles of solute / volume of solution in liters
Molarity (M) = 0.356 mol / 0.125 L
Molarity (M) = 2.848 M
Therefore, the molarity of the HCl solution is 2.848 M. The value you provided (3791.944 M) is not correct.