what is the molarity of a HCl solution that contains 13.0 g of HCl in 125 mL of solution?
Answer in units of M
moles = grams/molar mass.
Then M = moles/L soln.
3791.944?
I don't think so. Show your work and I'll find the error.
To determine the molarity (M) of a solution, you need to know the moles of solute (HCl) and the volume of the solution.
Step 1: Calculate the number of moles of HCl:
Use the formula:
moles = mass / molar mass
The molar mass of HCl is:
Molar mass = (1.01 g/mol for H) + (35.45 g/mol for Cl) = 36.46 g/mol
moles of HCl = mass of HCl / molar mass of HCl
= 13.0 g / 36.46 g/mol
= 0.357 mol
Step 2: Convert the volume of the solution from mL to L:
1 L = 1000 mL
125 mL = 125 mL * (1 L / 1000 mL)
= 0.125 L
Step 3: Calculate the molarity (M) of the solution:
Molarity (M) = moles / volume(L)
= 0.357 mol / 0.125 L
= 2.856 M
Therefore, the molarity of the HCl solution is 2.856 M.