The diagonal of a square has length square root 2 X s, where s is the length of a side of the square. What is the length of the diagonal in a square with sides that are 13 cm? Round your answer to the nearest tenth.

well, duh: 13*sqrt(2) = 13*1.414 = . . .

No its isn't that I found how you do it that would part of it.

To find the length of the diagonal of a square, we can use the Pythagorean theorem since the diagonal, the sides of the square, and a right triangle can be formed.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the diagonal) is equal to the sum of the squares of the lengths of the other two sides.

In this case, let's represent the length of the diagonal as d and the length of a side of the square as s.

According to the given information, we have the equation:
d^2 = s^2 + s^2 (using the Pythagorean theorem)

Simplifying this equation, we have:
d^2 = 2s^2

To find d, we take the square root of both sides:
d = sqrt(2s^2)

Substituting the value of s, which is 13 cm, into the equation, we get:
d = sqrt(2 * 13^2)
d = sqrt(2 * 169)
d = sqrt(338)

To approximate the length to the nearest tenth, we can use a calculator or a math software to evaluate the square root of 338. The result is approximately 18.4.

So, the length of the diagonal of the square with sides that are 13 cm is approximately 18.4 cm.