A rabbit runs in a horizontal straight line ABC across a field
(a)the rabbit runs from rest at A with a constant acceleration of 0.8 m/s^2 and reaches B after 3 seconds, find its speed at B
2.4
Vb=a*t=.8*3 m/s
To find the speed of the rabbit at B, we can use the equation:
v = u + at
Where:
v = final velocity (speed) at point B
u = initial velocity (speed) at point A
a = acceleration
t = time taken
Given:
u = 0 m/s (rest)
a = 0.8 m/s^2
t = 3 seconds
Plugging in these values into the equation, we have:
v = 0 + (0.8 * 3)
v = 0 + 2.4
v = 2.4 m/s
Therefore, the speed of the rabbit at point B is 2.4 m/s.
To find the speed of the rabbit at point B, we can use the equation:
v = u + at
where:
v = final velocity (speed at point B)
u = initial velocity (speed at point A)
a = acceleration
t = time
In this case, the initial velocity (speed at point A) is 0 because the rabbit starts from rest. The acceleration is given as 0.8 m/s^2, and the time taken is 3 seconds.
Plugging in these values into the equation:
v = 0 + (0.8 m/s^2)(3 s)
= 0 + 2.4 m/s
= 2.4 m/s
Therefore, the speed of the rabbit at point B is 2.4 m/s.