Can anyone check this answer for me,
simultaneous equation.
Where y = 14 + 0.11x
and y = 10 + 0.14x
use algebra to solve,
is the answer
14 + 0.11x = 10 + 0.14x
y = 4 x = 0.03
If not where am I going wrong
Thanks... :-)
Can anyone check this answer for me,
simultaneous equation.
Where y = 14 + 0.11x
and y = 10 + 0.14x
use algebra to solve,
is the answer
14 + 0.11x = 10 + 0.14x OK to here.
14-10=0.14x-0.11x
4=0.03x
x=4/0.03=133.3
y = 4 x = 0.03
If not where am I going wrong
Thank you for help !!!
To check the answer, we need to substitute the values of x and y into both equations and see if they satisfy both equations simultaneously.
The given equations are:
1) y = 14 + 0.11x
2) y = 10 + 0.14x
Substituting the values of x and y from the answer (x = 0.03, y = 4) into each equation:
1) 4 = 14 + 0.11(0.03)
2) 4 = 10 + 0.14(0.03)
Evaluating these equations step by step:
1) 4 = 14 + 0.0033
4 = 14.0033
2) 4 = 10 + 0.0042
4 = 10.0042
As you can see, neither equation is satisfied by the given values of x = 0.03 and y = 4. Therefore, the answer 14 + 0.11x = 10 + 0.14x, y = 4, x = 0.03 is incorrect.
To find the correct answer, let's solve the simultaneous equations step by step:
1) y = 14 + 0.11x
2) y = 10 + 0.14x
To solve these equations, we can set them equal to each other:
14 + 0.11x = 10 + 0.14x
Now, we need to isolate x on one side by subtracting 0.11x and 10 from both sides:
4 = 0.03x
To solve for x, we divide both sides by 0.03:
4 / 0.03 = x
x ≈ 133.33
Now, substitute this value of x back into either equation to solve for y. Let's use the first equation:
y = 14 + 0.11(133.33)
y = 14 + 14.67
y ≈ 28.67
Therefore, the correct solution to the simultaneous equations is x ≈ 133.33 and y ≈ 28.67.