at 2 p.m., the level of the water in the pool was 10 feet. at 6 p.m., the level of water was 2 feet. find the constant rate of change in the water.
2 feet per hr I'm a college student so I'm always right with this easy stuff
10/2=2/6 so 8/4=2ft per hr
The level of water dropped 8 feet in 4 hours, so you divide 8 by 4 and you get 2 feet per hour
To find the constant rate of change in the water level, we need to calculate the change in the water level and divide it by the change in time.
The initial water level at 2 p.m. is 10 feet, and the water level at 6 p.m. is 2 feet. So, the change in the water level is 2 feet - 10 feet = -8 feet (note the negative sign indicates a decrease).
The change in time is 6 p.m. - 2 p.m. = 4 hours.
Now, divide the change in the water level (-8 feet) by the change in time (4 hours):
-8 feet / 4 hours = -2 feet/hour
Therefore, the constant rate of change in the water level is -2 feet per hour.
In 4 hours the water level dropped 8 feet.
8/4 = 2 feet per hour