At 50 fahrenheit the maximum amount of water vapor in air is 9g/m3 if the relative humidity is 40% what is the mass of water vapor in 1m3 of air
3.6
40% x 9 = ?
To calculate the mass of water vapor in 1m^3 of air, we can use the equation:
Mass of water vapor = Maximum amount of water vapor * Relative humidity
Given:
Maximum amount of water vapor at 50 degrees Fahrenheit = 9g/m^3
Relative humidity = 40%
Let's calculate the mass of water vapor in 1m^3 of air:
Mass of water vapor = 9g/m^3 * 0.40 = 3.6g
Therefore, the mass of water vapor in 1m^3 of air is 3.6 grams.
To find the mass of water vapor in 1m³ of air, we can use the formula:
Mass of water vapor = Maximum amount of water vapor * Relative humidity
Given:
Maximum amount of water vapor at 50°F = 9g/m³
Relative humidity = 40%
First, we need to convert the relative humidity from a percentage to a decimal:
Relative humidity = 40% = 0.4
Now we can calculate the mass of water vapor:
Mass of water vapor = 9g/m³ * 0.4 = 3.6g
Therefore, the mass of water vapor in 1m³ of air is 3.6 grams.