A stock solution was prepared by dissolving exactly 0.4000 g of pure ASA (180.16g/mol) in 10.00 mL of NaOH and heating the solution to a gentle boil. After cooling to room temperature, the solution was poured into a 250 ml volumetric flask and diluted to the mark with DI water. Calculate the concentration of ASA in the flask.
concn ASA = mols/L
0.4000 g ASA x (1 mol ASA/molar mass ASA) = mols.
To calculate the concentration of ASA in the flask, we need to know the amount of ASA in moles and the volume of the solution.
First, let's find the amount of ASA in moles:
Mass of ASA = 0.4000 g
Molar mass of ASA = 180.16 g/mol
Number of moles (n) = Mass of ASA / Molar mass of ASA
n = 0.4000 g / 180.16 g/mol
n ≈ 0.002221 mol
Next, we need to find the volume of the solution in liters:
Volume of solution = 250 ml = 0.250 L
Now, we can calculate the concentration of ASA in the flask:
Concentration (C) = Number of moles / Volume of solution
C = 0.002221 mol / 0.250 L
C ≈ 0.008884 M
Therefore, the concentration of ASA in the flask is approximately 0.008884 M.