A diver with a mass of 70.0 kg stands motionless at the top of a 3.0 m high diving platform. Calculate his speed when he enters the pool. Thanks so much for helping!
everyone on this website got down syndrome its 12am and i need answers for homework
sqrt(2gH)
H is the diving board height and g is the acceleration of gravity.
The mass does not matter.
this website is dumb.
To calculate the speed of the diver when entering the pool, you can use the principle of conservation of energy. The potential energy of the diver at the top of the platform is converted into kinetic energy when the diver enters the water.
Step 1: Calculate the potential energy of the diver at the top of the platform.
The potential energy (PE) is given by the equation PE = mgh, where m is the mass of the diver, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height of the platform.
PE = (70.0 kg) * (9.8 m/s^2) * (3.0 m)
PE = 2058 J
Step 2: Calculate the kinetic energy of the diver when entering the water.
The kinetic energy (KE) is given by the equation KE = (1/2)mv^2, where m is the mass of the diver and v is the speed of the diver.
KE = (1/2) * (70.0 kg) * v^2
Step 3: Apply the principle of conservation of energy.
According to the principle of conservation of energy, the potential energy at the top of the platform is equal to the kinetic energy when entering the pool.
PE = KE
2058 J = (1/2) * (70.0 kg) * v^2
Step 4: Solve for the speed.
Rearrange the equation to solve for v:
v^2 = (2058 J) / [(1/2) * (70.0 kg)]
v^2 = 2 * 2058 J / 70.0 kg
v^2 ≈ 58.8 m^2/s^2
v ≈ √(58.8 m^2/s^2)
v ≈ 7.67 m/s
Therefore, the speed of the diver when entering the pool is approximately 7.67 m/s.