N2(g) + H2(g) -> NH3(g) ; how many moles of NH3 is is produced when 0.67 moles of N2 reacts with H2?
N2 + 3H2 ==> 2NH3
Use the coefficients.
0.67 mol N2 x (2 mol NH3/1 mol N2) = 0.67 x (2/1) = ? mol NH3.
To determine how many moles of NH3 are produced, we need to use the balanced chemical equation for the reaction and the stoichiometry provided.
The balanced chemical equation for the reaction is:
N2(g) + 3H2(g) → 2NH3(g)
According to the stoichiometry of the reaction, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. This means that the ratio of moles of N2 to moles of NH3 is 1:2.
To find the number of moles of NH3 produced when 0.67 moles of N2 reacts, we can use the ratio:
0.67 moles N2 × (2 moles NH3 / 1 mole N2) = 1.34 moles NH3
Therefore, when 0.67 moles of N2 reacts with H2, it produces 1.34 moles of NH3.