A 10 kg block rests on a frictionless table and is whirled in a circle and kept in a radius of 1.6 m by a rope attached to a peg. What is the tension in the rope if the block has a linear speed of 18 m/s?
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Can you calculate M*V^2/R ?
To find the tension in the rope, we can use the concept of centripetal force. The tension in the rope provides the centripetal force required to keep the block moving in a circular path.
The centripetal force (F) can be calculated using the following formula:
F = (m * v^2) / r
where m is the mass of the block (10 kg), v is the linear speed of the block (18 m/s), and r is the radius of the circle (1.6 m).
Substituting the given values into the formula, we get:
F = (10 kg * (18 m/s)^2) / 1.6 m
Simplifying, we have:
F = (10 kg * 324 m^2/s^2) / 1.6 m
= 6480 N / 1.6 m
= 4050 N
Therefore, the tension in the rope is 4050 N.