A lukewarm bottle containing 800 grams of water is placed in a refrigerator. How many calories of heat must be removed from the water to chill its temperature from 55 C to 4 C?
To determine the number of calories of heat that must be removed from the water to chill its temperature, you can use the formula:
Q = m * c * ΔT
Where:
Q = heat transferred (in calories)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in calories/gram °C)
ΔT = change in temperature (in °C)
For water, the specific heat capacity (c) is approximately 1 calorie/gram °C.
Given:
m = 800 grams
ΔT = (55 - 4) °C = 51 °C
Let's substitute the values into the formula:
Q = 800 grams * 1 calorie/gram °C * 51 °C
Q = 40,800 calories
Therefore, approximately 40,800 calories of heat must be removed from the water to chill its temperature from 55 °C to 4 °C.