Light passes from medium 1 to medium 2 where n1>n2.

a)Sketch the incident reflected and refracted rays.

The refracted angle, A1 (measured from the surface normal) exceeds the incident angle, A2.

sinA2/sinA1= n1/n2 > 1

The reflected angle equals the angle in incidence, but is on the other side of the normal.

You draw the sketch.

http://www.doe.mass.edu/mcas/images/db/ghsphysq44.gif

contains a sketch of the situation, when the incident ray encounters a medium of lower refractive index.

To sketch the incident, reflected, and refracted rays when light passes from a medium where the refractive index (n) is greater to a medium where the refractive index is smaller, follow these steps:

1. Draw a horizontal line to represent the interface between the two mediums, labeling it as the boundary.

2. Draw a straight line perpendicular to the boundary line to represent the incident ray. Label it as "Incident Ray." This incident ray is the path of light when it enters medium 2.

3. Draw a line at an angle away from the boundary line to represent the reflected ray. Label it as "Reflected Ray." The reflected ray is the path of light when it bounces back into medium 1.

4. Use Snell's law to determine the angle of the refracted ray. Snell's law states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the refractive indices of the two mediums: n1*sinθ1 = n2*sinθ2.

5. Draw a line at an angle towards the boundary line, representing the refracted ray. Label it as "Refracted Ray." The refracted ray is the path of light when it enters medium 2.

Keep in mind that when moving from a medium with a higher refractive index to a lower one, the incident ray bends away from the normal, the angle of reflection equals the angle of incidence, and the angle of refraction is larger than the angle of incidence.

By following these steps, you should be able to sketch the incident, reflected, and refracted rays.