The atmospheric pressure above a swimming pool changes from 755 to 765mm of mercury.The bottom of the speed is a 12m x 24m rectangle.By how much does the force on the bottom of the pool increase?
What does "the bottom of the speed" mean?
Muliply the pool bottom area by the pressure change, which is
(10/760)*Po = 1333 N/m^2
The pool area is 12*24 = 288 m^2
To find the increase in force on the bottom of the pool, we need to calculate the change in pressure and then multiply it by the area of the bottom of the pool.
First, let's find the change in pressure:
Change in pressure = Final pressure - Initial pressure
Given that the atmospheric pressure changes from 755 mmHg to 765 mmHg:
Change in pressure = 765 mmHg - 755 mmHg = 10 mmHg
However, it is common to express pressure in units of pascal (Pa) or newton per square meter (N/m²). So, we need to convert mmHg to pascal before continuing further.
1 mmHg (millimeter of mercury) is equivalent to 133.3224 pascal (Pa).
So, the change in pressure can be calculated as:
Change in pressure = 10 mmHg * 133.3224 Pa/mmHg
Now, calculate the change in pressure in pascal:
Change in pressure = 10 mmHg * 133.3224 Pa/mmHg = 1333.224 Pa
Now, we can find the increase in force by multiplying the change in pressure by the area of the bottom of the pool.
Force = Pressure * Area
Given that the bottom of the pool is a 12 m x 24 m rectangle:
Area = Length * Width = 12 m * 24 m = 288 m²
Now, calculate the increase in force:
Increase in force = Change in pressure * Area = 1333.224 Pa * 288 m²
Therefore, the increase in force on the bottom of the pool is equal to 383,614.112 N (newton).