In our lab we had to experiment with an apparatus in order to find such things as the percent of KClO_3 in the solution..
Assume that you heated your sample too rapidly and some of the sample spattered onto the rubber stopper of the test tube. Will your calculated percent KClO_3 be too high, too low, or unaffected if you finish the experiment as written? Explain.
If some of the sample spattered onto the rubber stopper of the test tube, it could affect the accuracy of your calculated percent KClO3. This is because the spattered sample on the rubber stopper would not have been completely burned and converted into KClO3 as intended in the experiment.
To understand why this would affect the calculated percent KClO3, let's take a look at the experiment process. In this experiment, the KClO3 in the solution is heated, and it decomposes to form KCl and O2 gas. The O2 gas is captured and measured, and the percent of KClO3 in the solution is calculated based on the amount of O2 gas produced.
If some of the sample spattered onto the rubber stopper, the KClO3 in that spattered sample would not have decomposed completely to produce O2 gas. As a result, the amount of O2 gas measured would be lower than it should be, leading to an underestimation of the actual amount of KClO3 in the solution.
Therefore, if you finish the experiment as written, the calculated percent KClO3 will be too low.
You don't provide enough information to know what you've done in the lab.
By the way, please don't change screen names.