Calculus ap
Use implicit differentiation to find the slope of the tangent line to the curve XY^3 + XY = 5 at the point (3,2) .
asked by
lily

3Y^2 x dy+ Y^3 dx+ x dy+ y dx=0
dy(3xy^2+x)=dx(y+y^3)
dy/dx= slope= (y^3+y)/(3xy^2+x)
put in the x,y and solve.
check my work, I did it in a hurry.posted by bobpursley

i got the answer right thanks
posted by LILY
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