A monkey is sitting on a wood plate attached to a rope whose other end is passed over a tree branch, as shown in the figure. The monkey holds the rope and tries to pull it down. The combined mass of the monkey and the wood plate is 117 kg.

a) What is the minimum force the monkey has to apply to lift off the ground?

b) What applied force is needed to move the monkey with an upward acceleration of 2.71 m/s2?

c) Now assume there is a second monkey standing on the ground and pulling down the rope by himself. What is the minimum force this second monkey has to apply to lift the first monkey on the wood plate off the ground?

d) And what applied force is necessary so that the second monkey on the ground can move the first monkey on the wood plate with an upward acceleration of 2.71 m/s2?

I NEED ONLY ANSWERS OF ESCH QUESTÝONS.. ÝF ANYONE SOLVE THESE PROBLEM. I WÝSH TO SAY LÝKE A) B) C)... THANKS

a) To find the minimum force the monkey has to apply to lift off the ground, we need to consider the gravitational force acting on the monkey and the wood plate. The gravitational force can be calculated using the formula F = m * g, where F is the gravitational force, m is the combined mass of the monkey and the wood plate, and g is the acceleration due to gravity (approximately 9.8 m/s^2).

So the minimum force the monkey has to apply to lift off the ground is F = 117 kg * 9.8 m/s^2 = 1146.6 N.

b) To find the applied force needed to move the monkey with an upward acceleration of 2.71 m/s^2, we need to consider the net force acting on the system. The net force can be calculated using the equation F_net = m * a, where F_net is the net force, m is the combined mass of the monkey and the wood plate, and a is the desired upward acceleration.

Since we are looking for the applied force, we can rearrange the equation to solve for F_applied:
F_net = F_applied - F_gravity,
F_applied = F_net + F_gravity.

Plugging in the given values:
F_net = m * a = 117 kg * 2.71 m/s^2 = 317.07 N,
F_gravity = m * g = 117 kg * 9.8 m/s^2 = 1146.6 N.

So the applied force needed to move the monkey with an upward acceleration of 2.71 m/s^2 is:
F_applied = F_net + F_gravity = 317.07 N + 1146.6 N = 1463.67 N.

c) To find the minimum force the second monkey has to apply to lift the first monkey on the wood plate off the ground, we need to consider the gravitational force acting on the system. Since the second monkey is pulling down on the rope, the force they apply must be greater than or equal to the gravitational force.

So the minimum force the second monkey has to apply is the same as the gravitational force calculated in part a), which is 1146.6 N.

d) To find the applied force necessary for the second monkey on the ground to move the first monkey on the wood plate with an upward acceleration of 2.71 m/s^2, we need to consider the net force acting on the system.

Using the same equation as in part b), we have:
F_net = F_applied - F_gravity.

Plugging in the given values:
F_net = m * a = 117 kg * 2.71 m/s^2 = 317.07 N,
F_gravity = m * g = 117 kg * 9.8 m/s^2 = 1146.6 N.

Rearranging the equation to solve for F_applied:
F_applied = F_net + F_gravity = 317.07 N + 1146.6 N = 1463.67 N.

So the applied force necessary for the second monkey on the ground to move the first monkey on the wood plate with an upward acceleration of 2.71 m/s^2 is 1463.67 N.