(sqrt3+5 sqrt6)(sqrt3-5 sqrt6)

DRWLS-Just take the difference of the squares of the two terms, sqrt 3 and 5 sqrt6. Then you will have the answer. It will be a negative integer.

3sqrt is 9
6sq rt is 36
I add 5 to one and subtract 5 from the other? 50 and 55, then I am supposed to multiply? 50x55=2750? Or is the difference -5?

sqrt 6 is not 36. You got that backwards

The squares of the two terms (sqrt 3 and 5sqrt6) are 3 and 150. The answer is 3-150 = -147

To solve the expression (sqrt(3) + 5sqrt(6))(sqrt(3) - 5sqrt(6)), you can use the difference of squares formula. The formula states that (a + b)(a - b) = a^2 - b^2. In this case, a = sqrt(3) and b = 5sqrt(6).

Now let's substitute the values into the formula:
(sqrt(3) + 5sqrt(6))(sqrt(3) - 5sqrt(6)) = (sqrt(3))^2 - (5sqrt(6))^2

Simplifying:
= 3 - 25 * 6

Next, calculate the value:
= 3 - 150

Finally,
= -147

So the answer is -147.