In this current of 12 volts, the voltmeter registers a voltage drop of 4 volts across 1 resistor, what is the voltage drop across the other resistor?
To find the voltage drop across the other resistor, we can use Ohm's Law. Ohm's Law states that the voltage drop across a resistor is equal to the current flowing through it multiplied by its resistance.
Here's how we can calculate the voltage drop across the other resistor:
1. First, let's find the current flowing through the circuit. We know that the circuit has a voltage of 12 volts, so the current flowing through the circuit can be calculated using Ohm's Law: I = V / R, where I is the current, V is the voltage, and R is the resistance.
2. Since the only known voltage drop is 4 volts and it occurs across one resistor, the voltage across this resistor is 4 volts. Let's assume this resistor has a resistance of R1.
3. Using Ohm's Law, we can calculate the current flowing through this resistor: I1 = V1 / R1, where I1 is the current, V1 is the voltage drop across one resistor (4 volts), and R1 is the resistance of the resistor.
4. Now, to find the voltage drop across the other resistor, we need to know the current flowing through it. Since the resistors are in series, the current flowing through both resistors is the same. Therefore, the current flowing through the other resistor (let's assume it has a resistance of R2) is also I1.
5. Finally, we can calculate the voltage drop across the other resistor using Ohm's Law: V2 = I1 * R2, where V2 is the voltage drop across the other resistor, I1 is the current (which we found in step 3), and R2 is the resistance of the other resistor.
By following these steps, you can find the voltage drop across the other resistor. Just plug in the values for V1, R1, and R2, which are given in the problem, and calculate the result.