a 1000 kg car is driven at 20 m/s. How many seconds would it take a 2000 N force to stop the car?

a = F/m would be the deceleration rate. That is 2 m/s^2.

The time required to reach zero velocity is
t = Vo/a = 20/2 = 10 seconds

The car would travel (Vo/2)*t = 100 meters during that deceleration time.

What is the kinectic energy of a body of mass 2000kg moving with a velocity of 10m/s

To find the time it would take for a force to stop the car, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration:

F = m * a

In this case, the force applied is 2000 N, and the mass of the car is 1000 kg. We need to find the acceleration of the car. The formula to calculate acceleration is:

a = (final velocity - initial velocity) / time

The final velocity is 0 m/s because the car comes to a stop. The initial velocity is 20 m/s. Rearranging the formula, we get:

time = (final velocity - initial velocity) / acceleration

Since the final velocity is 0 m/s, the formula becomes:

time = - initial velocity / acceleration

Now, we can substitute the given values:

time = -20 m/s / acceleration

To find the acceleration, we can use Newton's second law again:

F = m * a

Rearranging the formula for acceleration, we get:

a = F / m

Substituting the given values:

a = 2000 N / 1000 kg
a = 2 m/s^2

Now, we can substitute the acceleration value into the time formula:

time = -20 m/s / 2 m/s^2
time = -10 s

Since time cannot be negative, we take the absolute value:

time = 10 s

Therefore, it would take 10 seconds for a 2000 N force to stop the car.