An anagram is a rearrangement of all the letters in a word. Example: page--->gape, pgea..
a) Find the number of 7 letter anagrams possible for the letters in GUITARS.
I did 7!=5040...is that correct?
b) Find the probability of randomly choosing an anagram that starts with T.
There are 720 options for each letter because 5040/7=720. So 720/5040=1/7 which is answers...is this correct?
c) Mentally picture all of your 7-letter anagrams organized alphabetically in a long list, then write the first two and the last two in the list.
First two:
AGIRSTU
AGIRSUT
Last two:
UTSRIGA
UTSRIAG
Please let me know if these answers are correct
All correct, except the order of the last two anagrams:
should read:
UTSRIAG
UTSRIGA
Thank you very much:)
You're welcome! :)
a) Yes, your answer is correct. The number of 7-letter anagrams possible for the letters in GUITARS is indeed 7! = 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040.
b) Your approach is incorrect. While there are 720 different options for the first letter since there are 6 remaining letters after choosing 'T', the total number of anagrams is still 5040. Therefore, the probability of randomly choosing an anagram that starts with T is 720/5040 = 1/7. So your answer is correct.
c) The first two anagrams in the alphabetical list of 7-letter anagrams of GUITARS would be AGIRSTU and AGIRSUT. The last two anagrams would be UTSRIGA and UTSRIAG. So your answers for the first two and last two anagrams in the list are correct.