to multiply the sq rt of 3 cubed by the sq rt of 9 cubed I first need to factor them? So 9 3 times =729? and 3, 3 times is 9. Then multiply the two? to get 6561?
Or
Do I multiply 3 times 9 for 27 and add the 3+3 on the left of the radicand for 6?
Is my answer a whole number or in a radican?
to multiply the sq rt of 3 cubed by the sq rt of 9 cubed I first need to factor them? So 9 3 times =729? and 3, 3 times is 9. Then multiply the two? to get 6561?
Reading your words either way:
(sqrt(3))^3 x (sqrt(9))^3 =
3sqrt(3) x 27 = 81(sqrt(3))
...........OR............
sqrt(3^3) x sqrt(9^3))
3sqrt(3) x 27 = 81(sqrt(3))
Thank you. It is not the answer I have so I will rework it until I understnd.
Thanks again.
To multiply the square root of 3 cubed by the square root of 9 cubed, we can start by simplifying each term individually.
First, let's find the cube of 9. It means multiplying 9 by itself twice: 9 * 9 * 9 = 729. So you are correct that 9 cubed is equal to 729.
Next, let's find the cube of 3. Again, it means multiplying 3 by itself twice: 3 * 3 * 3 = 27. So 3 cubed is equal to 27.
Now that we have simplified the terms, we can multiply them together: sqrt(27) * sqrt(729).
This can be simplified as follows:
sqrt(27) = sqrt(9 * 3) = sqrt(9) * sqrt(3) = 3 * sqrt(3).
Similarly,
sqrt(729) = sqrt(9 * 81) = sqrt(9) * sqrt(81) = 3 * 9.
Now we can multiply the simplified terms:
(3 * sqrt(3)) * (3 * 9) = 9 * 3 * 3 * 9 = 729.
Therefore, the answer is 729, which is a whole number.