balance: SO2(g)+O2(g)------->SO3(g)
the concentration of SO2 and O2 are determined to be [0.06] and [0.03] if the following reaction has a Kc of 3.6x10^2, what is the concentration of SO3????
any work would be much appreciated thank you!!
............2SO2 + O2 ==> 2SO3
Is that [0.06] and [0.03] at equilibrium or is that how they started. If at equilibrium, then
Kc = (SO3)^2/(SO2)^2(O2)
You know Kc, SO2 and O2, solve for SO3 which is the only unknown in the equation.
To find the concentration of SO3, we can use the equilibrium expression and the given values of the concentration of SO2 and O2.
The balanced equation for the reaction is:
SO2(g) + O2(g) → SO3(g)
The equilibrium expression, Kc, can be written as:
Kc = [SO3] / [SO2] * [O2]
Given:
[SO2] = 0.06 M
[O2] = 0.03 M
Kc = 3.6x10^2
Now we can substitute these values into the equilibrium expression and solve for [SO3].
Kc = [SO3] / [SO2] * [O2]
3.6x10^2 = [SO3] / (0.06) * (0.03)
To isolate [SO3], we can rearrange the equation:
[SO3] = Kc * [SO2] * [O2]
Substituting the known values:
[SO3] = (3.6x10^2) * (0.06) * (0.03)
Calculating the value,
[SO3] = 0.648 M
Therefore, the concentration of SO3 is 0.648 M.