my science teacher showed us a diagram of a tiny light bulb on top of a D-cell battery,there was an electric wire touching the bottom of the light bulb.the electric wire was touching the bottom of the light bulb to the bottom of the battery.BUT, the other end of the electric wire wasn't touching the tip of the wire, it was touching the side of the wire.

The question was that do you think the light bulb will light up?

I said no. I know why its no, but I don't know how to explain it. I need at least 3 examples why I picked"no."

If there was insulation (look that word up), you are correct. If there was bare wire without insulation, you are wrong. Why?

you don't make sense

1. The light bulb needs both sides of the battery

2. Only one side of the battery is being touched by the wire
3. The second wire is touching rubber not metal

one kilogram is equal to

To explain why the light bulb will not light up in this scenario, you can consider the following three points:

1. Incomplete Circuit: For a circuit to function, there must be a complete path for the electric current to flow. The setup you described forms an incomplete circuit because the wire is touching the side of the battery's wire connector instead of the tip. As a result, the current cannot flow through the light bulb.

2. Lack of Conductivity: The side of the battery's wire connector usually does not have the same level of conductivity as the tip. The tip of the wire connector is designed to provide a better contact surface for current flow. When the wire is touching the side of the wire connector, it may not establish a secure connection, leading to poor or no conductivity.

3. Faulty Contact Point: When the wire touches the side of the battery's wire connector, the connection may be loose or unstable. This means that even if there is some conductivity, it may not be consistent enough to sustain a flow of electricity and provide the necessary amount of energy for the light bulb to light up.