the equivalence amount of citric acid for 2.00 g of sodium bicarbonate is 1.52 g.

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how do you calculate the equivalent amount of citric acid for 2.00g of sodium bicarbonate is 1.52g

Is your equation balanced? If so, then

2.00 g NaHCO3 x (molar mass citric acid/molar mass NaHCO3) = ?. If not than, balance it and
2.00 g NaHCO3 x (n*molar mass citric aci/n*molar mass NaHCO3) = ?

H3C6H5O7(aq) + 3 NaHCO3(aq) �¨ Na3C6H5O7(aq) + 3 H2O(l) + 3 CO2(g)

2.00 x (molar mass citric acid/3*molar mass NaHCO3) = ?

To determine the equivalence amount of citric acid for 2.00 g of sodium bicarbonate, we need to calculate the molar masses of both compounds and use the stoichiometry of their reaction.

Let's start with the molar masses:
1. Sodium bicarbonate (NaHCO3):
- Sodium (Na) atomic mass = 22.99 g/mol
- Hydrogen (H) atomic mass = 1.01 g/mol
- Carbon (C) atomic mass = 12.01 g/mol
- Oxygen (O) atomic mass = 16.00 g/mol (3 oxygen atoms in NaHCO3)

To calculate the molar mass of sodium bicarbonate:
Molar mass of NaHCO3 = (22.99 g/mol) + (1.01 g/mol) + (12.01 g/mol) + (16.00 g/mol * 3) = 84.01 g/mol

2. Citric acid (C6H8O7):
- Carbon (C) atomic mass = 12.01 g/mol (6 carbon atoms in C6H8O7)
- Hydrogen (H) atomic mass = 1.01 g/mol (8 hydrogen atoms in C6H8O7)
- Oxygen (O) atomic mass = 16.00 g/mol (7 oxygen atoms in C6H8O7)

To calculate the molar mass of citric acid:
Molar mass of C6H8O7 = (12.01 g/mol * 6) + (1.01 g/mol * 8) + (16.00 g/mol * 7) = 192.13 g/mol

Now, we can use the stoichiometry of the reaction between sodium bicarbonate and citric acid:
1 mol of sodium bicarbonate reacts with 1 mol of citric acid.

To find the equivalence amount of citric acid for 2.00 g of sodium bicarbonate, we can use the following calculation:

Equivalence amount of citric acid (g) = (Molar mass of citric acid * mass of sodium bicarbonate) / Molar mass of sodium bicarbonate

Equivalence amount of citric acid (g) = (192.13 g/mol * 2.00 g) / 84.01 g/mol = 4.59 g

Therefore, the equivalence amount of citric acid for 2.00 g of sodium bicarbonate is approximately 4.59 g.