how do u complete these questions?
2HCI(aq)+Pb(NO3)2(aq)--->
2HI(aq)+K2SO3(s)--->
Pb(NO3)2(aq)+2KCI(aq)--->
Ba(NO3)2(aq)+Na2SO4(aq)--->
K2CO3(aq)+Ba(NO3)2(aq)--->
HCI(aq)+AgNO3(aq)--->
Oh, I see you're testing my chemical reaction knowledge! Let's have some fun with these:
1. 2HCI(aq) + Pb(NO3)2(aq) → [Prepare yourself for a grand spectacle!] The lead (Pb) from the lead nitrate (Pb(NO3)2) will have a smashing time with the hydrochloric acid (HCI), resulting in the formation of some bubbly hydrogen iodide (HI) and a friendlier compound called potassium sulfite (K2SO3) for the party.
2. 2HI(aq) + K2SO3(s) → Chemistry gives us a chance to make weird combinations! The hydrogen iodide (HI) and potassium sulfite (K2SO3) will tango together, giving us potassium iodide (KI) and a solid substance, sodium chloride (NaCl).
3. Pb(NO3)2(aq) + 2KCI(aq) → Sometimes, opposites attract! When lead nitrate (Pb(NO3)2) and potassium chloride (KCI) team up, they will unleash the power of chemistry to create a duo of aqueous compounds: lead chloride (PbCl2) and potassium nitrate (KNO3).
4. Ba(NO3)2(aq) + Na2SO4(aq) → Brace yourself, chemistry is about to sprinkle its magic dust! Barium nitrate (Ba(NO3)2) and sodium sulfate (Na2SO4) will have a romantic encounter, resulting in the formation of barium sulfate (BaSO4) and a friendly compound, sodium nitrate (NaNO3).
5. K2CO3(aq) + Ba(NO3)2(aq) → Are you ready for this explosion of awesomeness? Potassium carbonate (K2CO3) teams up with barium nitrate (Ba(NO3)2) to create an explosive partnership! Brace yourself for the majestic formation of barium carbonate (BaCO3) and potassium nitrate (KNO3).
6. HCI(aq) + AgNO3(aq) → Get ready to witness some magical chemistry here! The hydrochloric acid (HCI) takes a dip with silver nitrate (AgNO3), resulting in the formation of some spectacular silver chloride (AgCl) and aqueous nitric acid (HNO3).
Remember to handle chemicals with care and always have some lab goggles handy!
To complete these questions, you need to balance the chemical equations by ensuring that the number of atoms on both sides of the equation is equal. Here's a step-by-step explanation for each question:
1. 2HCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2HNO3(aq)
To balance this equation, you need to ensure that the number of Cl and H atoms are equal on both sides. In this case, you have 2 chloride ions on the left and only 1 chloride ion on the right. Thus, you need to put a coefficient of 2 in front of HCl to balance the Cl atoms. Additionally, you need to put a coefficient of 2 in front of HNO3 to balance the H atoms. This gives you the balanced equation above.
2. 2HI(aq) + K2SO3(s) → 2KHI(aq) + SO2(g)
Here, you need to ensure that the number of I and H atoms are equal on both sides. To balance the I atoms, put a coefficient of 2 in front of HI. To balance the H atoms, no additional coefficient is needed because there is already 1 H atom on each side. Finally, no coefficients are required to balance the K and S atoms. The balanced equation is shown above.
3. Pb(NO3)2(aq) + 2KCl(aq) → PbCl2(s) + 2KNO3(aq)
In this equation, you only need to balance the number of Pb, Cl, and K atoms. By putting a coefficient of 2 in front of KCl, you will have 2 chloride ions on both sides. This also balances the potassium atoms. The lead (Pb) and nitrate (NO3) ions remain balanced. Therefore, the equation becomes balanced as shown above.
4. Ba(NO3)2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaNO3(aq)
To balance this equation, you need to ensure that the number of Ba, N, O, and Na atoms are equal. By putting a coefficient of 1 in front of Ba(NO3)2 and Na2SO4, the lead (Ba) and sodium (Na) atoms remain balanced. The nitrate (NO3) ions are also balanced. Finally, by putting a coefficient of 1 in front of BaSO4 and 2 in front of NaNO3, you balance the sulfur (S) atoms as well. The balanced equation is shown above.
5. K2CO3(aq) + Ba(NO3)2(aq) → BaCO3(s) + 2KNO3(aq)
To balance this equation, you need to ensure that the number of Ba, C, O, K and N atoms are equal. By putting a coefficient of 1 in front of K2CO3 and BaCO3, you balance the potassium (K) and carbon (C) atoms. The barium (Ba) atoms are also balanced. The nitrate (NO3) ions, oxygen (O) atoms, and nitrogen (N) atoms are already balanced. The balanced equation is shown above.
6. HCl(aq) + AgNO3(aq) → AgCl(s) + HNO3(aq)
To balance this equation, you need to ensure that the number of Cl, H, Ag, and N atoms are equal. By putting a coefficient of 1 in front of HCl and AgCl, you balance the chlorine (Cl) atoms. The hydrogen (H), silver (Ag), and nitrate (NO3) ions remain balanced. The balanced equation is shown above.
To complete these questions, you need to understand chemical reactions and be familiar with the rules of chemical equation balancing. Here's a step-by-step explanation of how to solve each equation:
1. 2HCI(aq) + Pb(NO3)2(aq) --->
To balance this equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Start with balancing the hydrogen (H) and chlorine (Cl) atoms. In this case, you can see that the chloride (Cl) atoms are already balanced, so let's balance the hydrogen atoms next. To do that, you can put a coefficient of 2 in front of HCl, making it 2HCl(aq). This gives you:
2HCl(aq) + Pb(NO3)2(aq) --->
Finally, check for the lead (Pb) and nitrate (NO3) atoms. There are 2 nitrate ions in Pb(NO3)2, so you need 2 NO3 ions on the left side of the equation. Therefore, the balanced equation is:
2HCl(aq) + Pb(NO3)2(aq) ---> 2HCI(aq) + Pb(NO3)2(aq)
2. 2HI(aq) + K2SO3(s) --->
Similarly, start by balancing the hydrogen (H) and iodine (I) atoms. Since there are 2 iodine atoms on the left, you need 2 HI molecules on the right side of the equation.
2HI(aq) + K2SO3(s) ---> 2HI(aq) + K2SO3(s)
Now, check for the potassium (K) and sulfur (S) atoms. There are 2 potassium ions (K+) and 1 sulfur atom (S) on the right side, but none on the left. To balance this, put a coefficient of 2 in front of K2SO3:
2HI(aq) + 2K2SO3(s) ---> 2HI(aq) + K2SO3(s)
3. Pb(NO3)2(aq) + 2KCI(aq) --->
Here, you have lead (Pb), nitrate (NO3), potassium (K), and chloride (Cl) ions. The lead atom is already balanced, so let's balance the other atoms. There are 2 nitrate ions (NO3) in Pb(NO3)2, so you need 2 potassium chloride (KCI) molecules to balance the number of chloride ions (Cl-). The balanced equation is:
Pb(NO3)2(aq) + 2KCI(aq) ---> Pb(NO3)2(aq) + 2KCI(aq)
4. Ba(NO3)2(aq) + Na2SO4(aq) --->
Start by balancing the barium (Ba), nitrate (NO3), sodium (Na), and sulfur (S) atoms. There are 2 nitrate ions (NO3) in Ba(NO3)2, so you need 2 sodium sulfate (Na2SO4) molecules to balance the number of sulfate ions (SO4-). This gives you:
Ba(NO3)2(aq) + Na2SO4(aq) ---> Ba(NO3)2(aq) + Na2SO4(aq)
5. K2CO3(aq) + Ba(NO3)2(aq) --->
Balance the potassium (K), carbon (C), oxygen (O), barium (Ba), and nitrate (NO3) atoms. You can see that there are 2 potassium ions (K+) and 2 nitrate ions (NO3-) in K2CO3 and Ba(NO3)2, respectively. Therefore, the balanced equation is:
K2CO3(aq) + Ba(NO3)2(aq) ---> K2CO3(aq) + Ba(NO3)2(aq)
6. HCI(aq) + AgNO3(aq) --->
Here, you have hydrogen (H), chloride (Cl), silver (Ag), and nitrate (NO3) ions. The hydrogen and chloride atoms are already balanced, so let's balance the silver and nitrate atoms. There is 1 silver atom (Ag) on the right side, so you need 1 HCl molecule to balance it. Therefore, the balanced equation is:
HCl(aq) + AgNO3(aq) ---> HCl(aq) + AgNO3(aq)
2HCl(aq) + Pb(NO3)2(aq) ==> PbCl2(s) + 2HNO3(aq)
You need the solubility rules to do the others (except for #2. That one is
2HI(aq) + K2SO3(s) ==> H2SO3(aq) + 2KI(aq)
Here is the solubility chart.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html