A comet experiences uniform acceleration from 60 m/s to 183 m/s in 10.0. what is the rate of acceleration
a. 6.0 m/s^2
b. 12.3 m/s^2
c. 18.3 m/s^2
d. 24.3 m/s^2
Divide the velocity change by the time interval (10.0 SECONDS), and see which number agrees.
You omitted the time dimension. That is a no-no.
umm its 18.3 m/s ^2
No it isn't. The velocity change is 123 m/s
To find the rate of acceleration, we can use the formula:
Acceleration = (Final Velocity - Initial Velocity) / Time
Given:
Initial Velocity (u) = 60 m/s
Final Velocity (v) = 183 m/s
Time (t) = 10.0 s
Plugging in the values into the formula, we get:
Acceleration = (183 m/s - 60 m/s) / 10.0 s
Simplifying the equation, we have:
Acceleration = 123 m/s / 10.0 s
Acceleration = 12.3 m/s^2
So, the rate of acceleration is 12.3 m/s^2
Therefore, the correct answer is b. 12.3 m/s^2