a carpainter made 20 pieces of furniture comprising of 74 legs. stool of 3 legs and chairs of 4 legs. How many chairs and stools did he make.
18 chairs and six stools
3 s + 4 c = 74
s+c=20 so s = (20-c)
3(20-c) + 4 c = 74
60 + c = 74
c = 14
s = 6
I don't no
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What math problem could cindy solve using the blocks?
Thanks fo the answer Cassie "18 chairs and six stools" Can you show me the working please.
"a carpainter made 20 pieces of furniture comprising of 74 legs. stool of 3 legs and chairs of 4 legs. How many chairs and stools did he make"
To find out how many chairs and stools the carpenter made, we can use a system of equations.
Let's assume the carpenter made x stools and y chairs.
Each stool has 3 legs, so the total number of legs from stools would be 3x.
Each chair has 4 legs, so the total number of legs from chairs would be 4y.
According to the given information, the total number of furniture pieces made is 20 and the total number of legs is 74.
So, we can set up the following system of equations:
x + y = 20 (equation 1)
3x + 4y = 74 (equation 2)
To solve this system, we can use the substitution method or elimination method.
Using the substitution method:
From equation 1, we can express x in terms of y:
x = 20 - y
Now, substitute the value of x in equation 2:
3(20 - y) + 4y = 74
Simplify the equation:
60 - 3y + 4y = 74
60 + y = 74
y = 74 - 60
y = 14
Now, substitute the value of y back into equation 1 to find x:
x + 14 = 20
x = 20 - 14
x = 6
Therefore, the carpenter made 6 stools and 14 chairs.