How long, to the nearest year, will it take me to become a millionaire if I invest $1000 at 10% interest compounded continuously?

I got 70 years, but it is wrong.
I used the P (1+ (r/m))^mt

Thank you.

To calculate the time it takes for an investment to reach a specific amount, we can use the continuous compound interest formula: A = P * e^(rt), where A is the final amount, P is the principal investment, r is the interest rate, and t is the time in years.

In this case, your principal investment is $1000, the interest rate is 10% (or 0.10), and you want to reach $1 million.

We can rearrange the formula to solve for t: t = ln(A/P) / r

Plugging in the values, we have:

t = ln(1000000/1000) / 0.10

Calculating this equation, we find:

t ≈ ln(1000) / 0.10 ≈ 6.9078 / 0.10 ≈ 69.08 years

Therefore, it will take approximately 69 years to become a millionaire with a $1000 investment at 10% interest compounded continuously.

To calculate the number of years it will take for an investment to grow to a certain amount, you can use the formula for compound interest:

A = P * e^(rt)

Where:
A = the final amount
P = the initial principal (investment amount)
r = annual interest rate (as a decimal)
t = number of years
e = the mathematical constant (approximately 2.71828)

In your case, you have an initial investment of $1000 and an annual interest rate of 10% (0.10), compounded continuously. You want to find the value of t, the number of years it will take for your investment to reach $1 million.

The formula now becomes:
$1,000,000 = $1000 * e^(0.10 * t)

To solve for t, divide both sides of the equation by $1000:
$1,000 = e^(0.10 * t)

Next, isolate the exponent on the right-hand side of the equation by taking the natural logarithm (ln) of both sides. This will remove the base e:
ln($1,000) = ln(e^(0.10 * t))

The natural logarithm of e^(0.10t) is simply 0.10t, so the equation simplifies to:
ln($ 1,000) = 0.10 * t

Now, divide both sides by 0.10:
ln($ 1,000) / 0.10 = t

Using a calculator, evaluate ln($ 1,000) / 0.10 ≈ 23.03.
Therefore, it will take approximately 23 years to become a millionaire with an initial investment of $1000 at 10% interest, compounded continuously.