How much work is required to lift a 280 kg refrigerator to the second-story level that is 6m high?
1.6*10^4 J
To determine the amount of work required to lift the refrigerator, we need to calculate the gravitational potential energy. The formula for gravitational potential energy is:
Gravitational potential energy = mass × acceleration due to gravity × height
Given:
Mass of the refrigerator = 280 kg
Height = 6 m
The acceleration due to gravity is approximately 9.8 m/s².
Using the formula, we can calculate the work required:
Gravitational potential energy = 280 kg × 9.8 m/s² × 6 m
= 16,632 Joules
Therefore, the work required to lift the refrigerator to the second-story level is 16,632 Joules.
To calculate the work required to lift the refrigerator to the second-story level, we can use the formula:
Work = Force × Distance
First, we need to calculate the force required to lift the refrigerator. The force required is equal to the weight of the refrigerator, which can be calculated using the formula:
Weight = Mass × Gravitational Acceleration
The mass of the refrigerator is given as 280 kg, and the gravitational acceleration is approximately 9.8 m/s².
Weight = 280 kg × 9.8 m/s² = 2,744 N
Next, we need to calculate the distance over which the refrigerator is lifted, which is given as 6 meters.
Now we can substitute the values into the work formula:
Work = Force × Distance
= 2,744 N × 6 m
= 16,464 Joules
Therefore, the work required to lift a 280 kg refrigerator to a height of 6 meters is 16,464 Joules.