Would someone please be kind enough to explain steps for this one. Thank you.
If m and n are positive integers and m is 250% of n, what percent of m is 2n?
m = 2.5n
2m = 5n
n = (2/5)m
2n = (4/5)m
4/5 = .8 = 80%
e.g.
let n = 10, then m = 25
then 2n = 20
percentage of 25 is 20 --> 20/25 = .8 = 80%
thank you reiny i really needed it thank you soo much!!
To find what percent of m is 2n, we need to compare 2n to m in terms of percentages.
Step 1: Let's start by understanding the given information. In the problem, it is stated that m is 250% of n. This means that m is 2.5 times larger than n. We can express this as an equation:
m = 2.5n
Step 2: Now, let's find what percent of m is 2n by setting up a ratio. To do this, we can divide 2n by m:
(2n/m)
Step 3: To express this ratio as a percentage, we need to multiply it by 100. This will give us the answer in terms of a percentage:
(2n/m) * 100
Step 4: Substitute the expression for m from Step 1 into the ratio expression:
(2n/(2.5n)) * 100
Step 5: Simplify the expression:
(2/2.5) * 100
Step 6: Calculate the ratio:
0.8 * 100
Step 7: Finally, multiply the ratio by 100 to express it as a percentage:
80%
Therefore, 2n is 80% of m.