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There is 10 white,9 black and 7 red balls in a bucket,In how many ways we can select one or more balls?
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"Or more" is very vague. It could possibly include all the balls.
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A basket contains some white, red and black ball. There are 15 white and red balls. There are 18 red and black balls. The number
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w+r = 15 r+b = 18 b+w = 9 substitution might be easiest or, maybe this will look easier 0b+1r+1w =
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A bag contains 6 black balls,5 red balls and 4 white balls,if 3 are selected at random without replacement determine the
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The probability of all events occurring is found by multiplying the probabilities of each events.
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A bag contains 6 black balls,5 red balls and 4 white balls,if 3 are selected at random without replacement determine the
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To determine the probabilities of the given cases, we will use the concept of combinations and
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in a bag there are 20 red 30black 40 blue50 white balls. what is the minimum number of balls to be drawn without replacement so
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Red is the hardest to get, since there are only 20 of them. To make sure you get <i>some</i> red,
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a. The probability of picking a black ball is 2/11. (There are 2 black balls out of a total of 11
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A bag contains three black balls, four white balls and five red balls. Three balls are removed without replacement. What is the
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Try the rest now.
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A bag contain three black balls,four white balls and five red balls.Three balls are removed without replacement.What is the
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So you want BWR that particular order's prob = (3/12)(4/11)(5/10) = 1/22 but the BWR can be arranged
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a box contains 20 red,30 black,40 blue,50 white. what will be the minimum number of balls to be drawn without replacement so
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Answered by MathMate a few days ago under a Physics heading
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You have a bucket with 3 black balls and 7 red balls. What is the probability of drawing 2 reds and 1 black in 3 draws if order
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ways to do this: RRB RBR BRR so three ways, then Pr= 3*7/10*7/10*3/10
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Chris had some black and white balls in a box. First, he added 98 white balls and as a result, 40% of the balls were black.
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…
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